SOLUTION: I need some help solving for p {{{(x-1)(x^2-4)+2(x-1)(x+2)=(x-1)*p}}}

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Question 243552: I need some help solving for p %28x-1%29%28x%5E2-4%29%2B2%28x-1%29%28x%2B2%29=%28x-1%29%2Ap
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-1%29%28x%5E2-4%29%2B2%28x-1%29%28x%2B2%29=%28x-1%29%2Ap Start with the given equation.


%28x-1%29%28%28x%5E2-4%29%2B2%28x%2B2%29%29=%28x-1%29%2Ap Factor out the GCF x-1


%28x-1%29%28%28x%5E2-4%29%2B2%28x%2B2%29%29%2F%28x-1%29=p Divide both sides by x-1 to isolate 'p'.


cross%28%28x-1%29%29%28%28x%5E2-4%29%2B2%28x%2B2%29%29%2Fcross%28%28x-1%29%29=p Cancel out the common terms.


%28x%5E2-4%29%2B2%28x%2B2%29=p Simplify


p=%28x%5E2-4%29%2B2%28x%2B2%29 Rearrange the equation.


p=x%5E2-4%2B2x%2B4 Distribute


p=x%5E2%2B2x Combine like terms.