Question 243079: The product of two numbers is 128 and their quotient is 8. What are the numbers?
Found 2 solutions by sarrobbi, MathTherapy:
Answer by sarrobbi(2)   (Show Source):
You can put this solution on YOUR website! The answer is 32, and 4.
A quotient is the answer to a division problem. In this case 32/4 = 8 where eight is the quotient.
32x4=128.
32 and 4 both work as dividends and multipliers.
Answer by MathTherapy(10549)  (Show Source):
You can put this solution on YOUR website! The product of two numbers is 128 and their quotient is 8. What are the numbers?
Let the 1st number be F, and the 2nd S
Since their product is 128, we can say that FS = 128 -------- (i)
Also, since their quotient is 8, then we can say that  ------ (ii)
Solving for F in eq (ii), we get: F = 8S
Substituting 8S for F in eq (i), we get: 8S(S) = 128
 -------- 
 -------- Factoring out GCF, 8
 -------- (S - 4)(S + 4) = 0
Therefore, S, or the 2nd number is 4, or - 4
If the 2nd number is 4, then the 1st number is F(4) = 128, which makes F = 32
If the 2nd number is -4, then the 1st number is F(-4) = 128, which makes F = -32
Therefore, the numbers are either  , or  .
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