SOLUTION: Word Problem: I have to write a linear equation and graph on coordinate plane; got stuck Band A charges $600 to play for the entire evening Band B charges $350 plus $1.25 fo

Algebra ->  Graphs -> SOLUTION: Word Problem: I have to write a linear equation and graph on coordinate plane; got stuck Band A charges $600 to play for the entire evening Band B charges $350 plus $1.25 fo      Log On


   



Question 243073: Word Problem:
I have to write a linear equation and graph on coordinate plane; got stuck
Band A charges $600 to play for the entire evening
Band B charges $350 plus $1.25 for each ticket sold.
Write a linear equation for the cost of each band
Find the number of tickets for which the cost of the two bands will be equal.
This was what I thought was right, but couldn't graph properly...could you tell me where I went wrong? Thank you.
x = tickets
y= cost for band
y=600
y=1.25x + 350

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Word Problem:
I have to write a linear equation and graph on coordinate plane; got stuck
Band A charges $600 to play for the entire evening
Band B charges $350 plus $1.25 for each ticket sold.
Write a linear equation for the cost of each band
Find the number of tickets for which the cost of the two bands will be equal.
This was what I thought was right, but couldn't graph properly...could you tell me where I went wrong? Thank you.
x = tickets
y= cost for band
y=600
y=1.25x + 350;
:
But what you have is right.
If you graph these:
y = 600 ( a horizontal line)
and
y = 1.25x + 350
:
Looks like this:
+graph%28+300%2C+200%2C+-100%2C+300%2C+-200%2C+700%2C+600%2C+1.25x%2B350%29+
Find the no. of tickets when they are equal;
1.25x + 350 = 600
1.25x = 600 - 350
1.25x = 250
x = 250%2F1.25
x = 200 tickets; which is confirmed on the graph