SOLUTION: how do you factor 8x^2-22x+5=0
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Question 243064
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how do you factor
8x^2-22x+5=0
Answer by
stanbon(75887)
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how do you factor
8x^2-22x+5=0
8x^2 -20x -2x+5 = 0
4x(2x-5)-(2x-5) = 0
(2x-5)(4x-1) = 0
x = 5/2 or x = 1/4
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Cheers,
Stan H.
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