SOLUTION: Find the length of a rectangular 10t with a perimeter of 108 meters if the length is 8 meters more than the width. use formula P= 2L+ 2W

Algebra ->  Surface-area -> SOLUTION: Find the length of a rectangular 10t with a perimeter of 108 meters if the length is 8 meters more than the width. use formula P= 2L+ 2W      Log On


   

Question 243008: Find the length of a rectangular 10t with a perimeter of 108 meters if the length is 8 meters more than the width. use formula P= 2L+ 2W
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
I cannot say was a "rectangular 10t" is, but I can solve the algebra.
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We are given the information to setup our work:
P = 2L + 2W = 108
L = W + 8
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Substituting we have:
2(W+8) + 2W = 108
2W + 16 + 2W = 108
4W = 92
W = 23
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Returning to the given information:
L = W + 8 = 23 + 8 = 31
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So the proposed answer is:
W = 23
L = 31
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Now we check our work.
Is the length 8 more than the width?
Yes, 31 is 8 more than 23.
Is the perimeter 108?
P = 2L + 2W = 2(31) + 2(23) = 62 + 46 = 108. Yes it is.
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Done except that I don't know what a "rectangular 10t" is.