SOLUTION: square root of p^2-3p+16 (the square root ends on top of 16)=p+1

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Question 242784: square root of p^2-3p+16 (the square root ends on top of 16)=p+1
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(p^2-3p+16)=p+1 square both sides.
p^2-3p+16=p^2+2p+1
-3p-2p=1-16
-5p=-15
p=-15/-5
p=3 ans.
Proof:
sqrt(3^2-3*3+16)=3+1
sqrt(9-9+16)=4
sqrt16=4
4=4