SOLUTION: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0      Log On


   



Question 242782: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
Found 3 solutions by MRperkins, stanbon, Edwin McCravy:
Answer by MRperkins(300) About Me  (Show Source):
You can put this solution on YOUR website!
so you have sqrt%284%2B6t%29-sqrt%281-8t%29=0 only it is cubed root instead of square root (I am just not sure how to get the 3 in place for the 2) it doesn't really matter anyways because we are going to get rid of them shortly! :)
move sqrt%281-8t%29 over to the right side of the equation and you get sqrt%284%2B6t%29=sqrt%281-8t%29
Now cube both sides and you get 4%2B6t=1-8t You should be able to solve it from here.
If you need any other questions answered, then you can email me at justin.sheppard.tech@hotmail.com

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
-------------------------------
cube root of (4+6t) - 3[the cube root of (1-8t)] = 0
------------------
cbrt(4+6t) = 3*cbrt(1-8t)
---
Raise both sides to the 3rd power
---
4+6t = 27(1-9t)
4+6t = 27 - 243t
249t = 23
t = 23/249
=============================
Cheers,
Stan H.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
I think this is what you are describing:

root%283%2C4%2B6t%29-root%283%2C1-8t%29=0

Add the opposite of second term to both sides:

root%283%2C4%2B6t%29=root%283%2C1-8t%29

Raise both sides to the 3 power:

%28root%283%2C4%2B6t%29%29%5E3=%28root%283%2C1-8t%29%29%5E3

When you raise a root to the same power as its index,
you take away the root and the exponent and just
leave what's underneath:

4%2B6t=1-8t

14t=-3

t=%28-3%29%2F14

t=-3%2F14

Edwin