SOLUTION: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0      Log On


   

Question 242781: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
Your question is not clear. The description you gave of the "square root" but with a 3 in in the radical is the "cube root" not the square root. The cube root of 27 is 3, which is 3*3*3, which is shown as 3^3.
If the (4+6t) has a little 3 exponent, then it is to the third power and the cube root is simply 4+6t. But I cannot say for sure from your description.