SOLUTION: Please help, can't find a good place to explain the process involved with solving. Solve (x + 2)(x-2)(x+1)=0 a)the solution set is b)solution is all real numbers c)there is

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help, can't find a good place to explain the process involved with solving. Solve (x + 2)(x-2)(x+1)=0 a)the solution set is b)solution is all real numbers c)there is       Log On


   



Question 242744: Please help, can't find a good place to explain the process involved with solving.
Solve
(x + 2)(x-2)(x+1)=0
a)the solution set is
b)solution is all real numbers
c)there is no solution

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve
(x + 2)(x-2)(x+1)=0
a)the solution set is
b)solution is all real numbers
c)there is no solution
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Since the product of the 3 binomials is zero, one of them has to be zero.
x+2 = 0 --> x = -2
x-2 = 0 --> x = +2
or
x+1 = 0 --> x = -1