Question 242631: If a number is divisible by both 4 and 9, by what other numbers is it divisible?Explain. Thank you.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! since 9 is not a multiple of 4, the smallest number that can be divisible by 4 and 9 has to be a number that is the result of a product of 4 * 9.
if it is divisible by 4 and 9, then it has to be divisible by factors of 4 and 9.
that means it is divisible by 2 and 3 as well.
it should also be divisible by any combination of the factors of 4 and 9.
since the factors would be 2*2*3*3, then:
that would be:
2*2 = 4
2*3 = 6
3*3 = 9
2*2*3 = 12
2*3*3 = 18
4*9 * anything else would yield even more possibilities/.
example:
4*9*2 = 72
since there's another factor in the mix, 72 should be divisible by even more numbers that are combinations of factors of 2*2*3*3*2
those would be:
2*2 = 4
2*3 = 6
3*3 = 9
2*2*3 = 12
2*3*3 = 18
plus:
2*2*2 = 8
2*2*3*2 = 24
2*3*3*2 = 36
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