SOLUTION: Solve the following rational expression: {{{3/(x+2)+ 5/(x+4)=2}}} I have been trying and have finished this question. I would just like to see if I have done it correstly. Than

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve the following rational expression: {{{3/(x+2)+ 5/(x+4)=2}}} I have been trying and have finished this question. I would just like to see if I have done it correstly. Than      Log On


   



Question 242579: Solve the following rational expression:
3%2F%28x%2B2%29%2B+5%2F%28x%2B4%29=2
I have been trying and have finished this question. I would just like to see if I have done it correstly. Thank you.

Found 2 solutions by nyc_function, MathTherapy:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
If you give me your e-mail, I can send a reply using paint attachment, which is far easier to read and follow. With paint, I can also draw geometric shapes.
I'll wait for your reply.
Write to: nycfunction@yahoo.com
Guido
P.S. Post one question at a time for a faster reply.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following rational expression:
3%2F%28x%2B2%29%2B+5%2F%28x%2B4%29=2
I have been trying and have finished this question. I would just like to see if I have done it correstly. Thank you.

It would've helped greatly if you'd included your answer. This way, a check could've been made to see if your answer is correct. better yet, you could've done the check yourself, and would've determined if your answer is correct.

3%2F%28x%2B2%29%2B+5%2F%28x%2B4%29=2

3(x + 4) + 5(x + 2) = 2(x + 2)(x + 4)----- Multiplying each side of the equation by its LCD, (x + 2)(x + 4) to clear the fractions

3x+%2B+12+%2B+5x+%2B+10+=+2%28x%5E2+%2B+6x+%2B+8%29

8x+%2B+22+=+2x%5E2+%2B+12x+%2B+16

0+=+2x%5E2+%2B+4x+-+6 ------ Subtracting 8x and 22 from both sides of equation

2x%5E2+%2B+4x+-+6+=+0 ------ Rearranging equation

2%28x%5E2+%2B+2x+-+3%29+=+2%280%29 ------ Factoring out GCF

(x + 3)(x - 1) = 0 ------ Factoring quadratic, x%5E2+%2B+2x+-+3+=+0

x = - 3, or 1

Since - 2 or - 4 would make the fractions in the equation undefined, then x CANNOT equal any of these 2 numbers. Since x DOES NOT equal - 2 or - 4, then x being equal to - 3 or 1 are the correct values. You can now do the check to make sure that they do work.