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Question 242261: Twice a first number plus a second number is 18. The first number is five less than three times the second number. Find the numbers. Show equations.
Answer by nyc_function(2741)   (Show Source):
You can put this solution on YOUR website! 2x + y = 18
x = 3y - 5
Those are your equations.
Can you finish now?
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I got your e-mail. Here is the entire problem solved.
Good morning. I got your reply lasy night. Here is how we do your math problem.
Twice a first number plus a second number is 18. The first number is five less than three times the second number. Find the numbers. Show equations.
Solution:
Let x = one number
let y = the other number
2x + y = 18
x = 3y - 5
I will use the substitution method, which is the easiest to follow.
Plug 3y - 5 into the other equation and solve for y.
2(3y - 5) + y = 18
6y - 10 + y = 18
7y = 18 + 10
7y = 28
y = 28/7
y = 4
Since we now know y = 4, we plug 4 for y into EITHER of the original equations created from the word problem.
I will use x = 3y - 5.
Let y = 4
x = 3(4) - 5
x = 12 - 5
x = 7
The numbers are 4 and 7.
Did you follow?
Guido
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