SOLUTION: The width of a rectangle is 42 years less than the length. The perimeter of the rectangle is 220 yards. Find the length and width of the rectangle.

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Question 242079: The width of a rectangle is 42 years less than the length. The perimeter of the rectangle is 220 yards. Find the length and width of the rectangle.
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
Once we've represented the width and length then we can set up an equation.
Let x be the length and x-42 be the width. Now we can set up how it will look.
x+x+(x-42)+(x-42)=220 Combine like terms, we get:
4x-84=220 Add 84 to both sides to get:
4x=304 Divide each side by 4 to result in:
x=76
Now we know the length is 76 yards and the width is 34 yards. To check it out, add these up. Remember there are 4 sides.
RJ Toftness
www.math-unlock.com