SOLUTION: How many pounds of coffee beans selling for $2.00 per pound should be mixed with 6 pounds of coffee beans selling for $2.80 per pound to obtain a mixture selling for $2.48 per poun

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many pounds of coffee beans selling for $2.00 per pound should be mixed with 6 pounds of coffee beans selling for $2.80 per pound to obtain a mixture selling for $2.48 per poun      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 24135: How many pounds of coffee beans selling for $2.00 per pound should be mixed with 6 pounds of coffee beans selling for $2.80 per pound to obtain a mixture selling for $2.48 per pound.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the number of lbs of coffee selling for $2.00/lb. You want to mix x lbs of $2.00 coffee beans with 6 lbs of $2.80 coffee beans to obtain a mixture of (6+x) lbs of $2.48 coffee beans. Let's set up the appropriate equation to solve this mystery:
x%282%29+%2B+6%282.8%29+=+%286%2Bx%29%282.48%29 Simplify and solve for x.
2x+%2B+16.8+=+14.88+%2B+2.48x Subtract 2x from both sides of the equation.
16.8+=+14.88+%2B+0.48x Subtract 14.88 from both sides.
1.92+=+0.48x Finally, divide both sides by 0.48
1.92%2F0.48+=+x
x+=+4
You will need to mix 4 lbs of the $2.00 coffee beans with 6 lbs of the $2.80 coffee beans to obtain 10 lbs of $2.48 coffee bean mixture.