SOLUTION: I need to solve this equation by factoring. x^3+5x^2-6x=0? So far, i have (x^2-?)(x+?), but i don't quite understand the factoring part for this equation. Please help.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I need to solve this equation by factoring. x^3+5x^2-6x=0? So far, i have (x^2-?)(x+?), but i don't quite understand the factoring part for this equation. Please help.       Log On


   

Question 24085: I need to solve this equation by factoring. x^3+5x^2-6x=0? So far, i have (x^2-?)(x+?), but i don't quite understand the factoring part for this equation. Please help.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First factor out the common factor of x:

+x%5E3%2B5x%5E2-6x=0
x%28x%5E2%2B5x-6%29=0
x%28x%2B6%29%28x-1%29+=+0

Set each factor equal to zero. There will be three solutions:

x= 0

x+6= 0
x=-6

x-1 = 0
x=1

R^2 at SCC