SOLUTION: I am stumped, i know you plug in the bottom formula but trying to solve it has me confused g(x)=x^2+3x h(x)=(x+3)/2 find (h*g)(-1)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I am stumped, i know you plug in the bottom formula but trying to solve it has me confused g(x)=x^2+3x h(x)=(x+3)/2 find (h*g)(-1)       Log On


   

Question 240669: I am stumped, i know you plug in the bottom formula but trying to solve it has me confused
g(x)=x^2+3x

h(x)=(x+3)/2

find (h*g)(-1)



Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
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g(x)=x^2+3x

h(x)=(x+3)/2

find (h*g)(-1)
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Multiply the two algebraic expressions; then evaluate that product at x=-1.
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(h*g)(-1) = [(x+3)/2](-1)
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[(x^3+3x^2)/2](-1)
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[(-1)^3+3(-1)^2]/2
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=[-1+3]/2
=[2/2]
= 1
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Cheers,
Stan H.
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