SOLUTION: {{{(4y^4+y^2)(y^2+y)}}} i have {{{4y^6+y^3}}} but do i have to add them too together or no?

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: {{{(4y^4+y^2)(y^2+y)}}} i have {{{4y^6+y^3}}} but do i have to add them too together or no?      Log On


   

Question 240446: %284y%5E4%2By%5E2%29%28y%5E2%2By%29 i have 4y%5E6%2By%5E3 but do i have to add them too together or no?
Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
4y%5E4%2Ay%5E2+=+4y%5E6
4y%5E4%2Ay+=4y%5E5
y%5E2%2Ay%5E2=y%5E4
y%5E2%2Ay=Y%5E3
Add them all together gives
4y%5E6%2B4y%5E5%2By%5E4%2By%5E3
Remember that in general y%5Ea%2By%5Eb does not equal y%5E%28a%2Bb%29