Question 240209: solve the exponential equation.
e^2x + e^x -6=0
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! e^2x + e^x -6=0
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This is simply a "quadratic equation":
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Let y = e^x
then
y^2 = (e^x)^2 = (e^x)(e^x) = e^2x
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So now we can rewrite:
e^2x + e^x -6=0
y^2 + y -6=0
(y+3)(y-2) = 0
y = {-3, 2}
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Since we said:
y = e^x
ln y = x
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So,
x = ln 2 (this is your solution)
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