SOLUTION: A painting covers 44 square inches one side of the painting is 3 inches more than twice the other side find the dimensions of the painting

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Question 240052: A painting covers 44 square inches one side of the painting is 3 inches more than twice the other side find the dimensions of the painting
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
L=2W+3
LW=44
(2W+3)W=44
2W^2+3W-44=0
(2W+11)(W-4)=0
W-4=0
W=4 ANS.
L=2*4+3
L=8+3
L=11 ANS.
PROOF:
11*4=44
44=44

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A painting covers 44 square inches one side of the painting is 3 inches more than twice the other side find the dimensions of the painting
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side = "x"
side = 2x+3
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Equation:
x(2x+3) = 44
2x^2 + 3x - 44 = 0
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x = [-3 +- sqrt(9 -4*2*-44)]/2
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x = [-3 +- sqrt(361)]/2
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Positive solution:
x = [-3 + 19]/2
x = 8 cm (one of the sides)
2x+3 = 19 (the other side)
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Cheers,
Stan H.