SOLUTION: how do you graph this system of linear inequalities... y is less than or equal to 2x+3 y>-x+5

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Question 23999: how do you graph this system of linear inequalities...
y is less than or equal to 2x+3
y>-x+5

Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
Diregard the other answers I sent to you. I pressed the wrong button.
Start by solving each inequality for y; and put in slope y-intercept form, y=mx+b;
y%3C=2x%2B3
y>-x+5
They both are already is in slope intercept form;
The first one;
your y-intercept = 3
secnd one;
y-intercept=5
So what you do on the graph is plot points at your y-intercept;
Now your first slope=2
second slope=-1
graph+%28500%2C+500%2C+-6%2C6%2C-6%2C6%2C+y%3C=2x%2B3%2C+y=-x%2B5%29
Now the important part is the shading. since the first eq. is < and = to, you are going to make it a solid line and shade the area BELOW the line.
The second eq.is > so you are going to make the line dotted and shade the area ABOVE the line.
Hope you understand
=)