Question 239926: how do i find all double roots of
s^3-27s=0 showing all the steps?
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! s^3 -27s =0
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s(s^2 -27) = 0
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s=0
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s^2 -27= 0
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s^2 =27
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s = +/- sqrt 27
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s= +/- sqrt(9*3)
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s= +/- sqrt 9 * sqrt3
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s = +/- 3sqrt3
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check,,s=0,,,,,0=0,,,ok
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s=+3sqrt3...(3sqrt3)^3 -27(3sqrt3) =0,,,ok
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s=-3sqrt3....(-3sqrt3)^3 -27(-3sqrt3) = 0,,,,,ok
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