SOLUTION: please help me solve this equtaion: {{{ 12t^2-13t=35 }}}

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Question 239908: please help me solve this equtaion: +12t%5E2-13t=35+
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
I am going to solve this using the master product method. You may not have learned how to do this method but I find it faster than the guess and check method.

so first we need to subtract 35 from both sides to get the equation into standard form.

12t^2-13t-35=0

Now we multiply 12 and -35 to get -420. Now we need to find factors of -420 that add to -13. This comes out to 15, -28. Now multiply those factors by t and plug those back into the original equation.

12t^2-28t+15t-35 = 0

Now factor by grouping

(12t^2-28t)+(15t-35) = 0
4t(3t-7)+5(3t-7) = 0
(4t+5)(3t-7) = 0

Now we set each factor equal to 0 and solve. I will leave this for you to do but you will eventually get t = -5/4 and t = 7/3.