SOLUTION: 2 logx= log(8x-160)+1

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Question 239806: 2 logx= log(8x-160)+1
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
2+logx=+log%28%288x-160%29%29%2B1
logx%5E2=+log%28%288x-160%29%29%2B1
logx%5E2+-+log%28%288x-160%29%29=+1
log%28%28x%5E2%2F%288x-160%29%29%29+=+1
x%5E2%2F%288x-160%29+=+10%5E1
x%5E2+%2F%288x-160%29+=+10
x%5E2+=+80x+-+1600
x%5E2+-+80x+%2B+1600=0
(((x-40)(x-40)=0}}}
x=40
Check your answer with a calculator. Does 2 log(40) = log(320-160) + 1 ???