SOLUTION: 40 grams of a 50% acid solution. How much water must be added to make a 10% solution
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Question 239567
:
40 grams of a 50% acid solution. How much water must be added to make a 10% solution
Answer by
checkley77(12844)
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.50*40=.10(40+x)
20=4+.10x
.10x=20-4
.10x=16
x=16/.10
x=160 grams of water is used.
Proof:
.50*40=.10(40+160)
20=.10*200
20=20