SOLUTION: Can someone please help me out? I am lost on this one. I am usually really good with factoring nomials but I have no clue as to how to deal with this one. factor: x^(2n+1)-2x^(n

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can someone please help me out? I am lost on this one. I am usually really good with factoring nomials but I have no clue as to how to deal with this one. factor: x^(2n+1)-2x^(n      Log On


   

Question 239239: Can someone please help me out? I am lost on this one. I am usually really good with factoring nomials but I have no clue as to how to deal with this one.
factor: x^(2n+1)-2x^(n+1)+x
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
factor: x^(2n+1)-2x^(n+1)+x
= x%2A%28x%5E%282n%29+-+2x%5En+%2B+1%29
= x%28x%5En+-+1%29%5E2

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E%282n%2B1%29+-+2x%5E%28n%2B1%29+%2B+x
x%2A%28x%5E%282n%29+-+2x%5En+%2B+1%29
x%2A%28x%5En+-+1%29%5E2 answer
I just factored it in my head, but completing
the square works, too
x%2A%28x%5E%282n%29+-+2x%5En+%2B+1%29
x%5E%282n%29+-+2x%5En+%2B+%28-2%2F2%29%5E2+=+-1+%2B+%28-2%2F2%29%5E2
x%5E%282n%29+-+2x%5En+%2B+1+=+-1+%2B+1
%28x%5En+-+1%29%5E2+=+0