SOLUTION: Against a head wind, Jeff computes his flight time for a trip of 2900 miles at 5 hours. The flight would take 4 hours and 50 minutes if the head wind were half as much. Find the he
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Question 239236: Against a head wind, Jeff computes his flight time for a trip of 2900 miles at 5 hours. The flight would take 4 hours and 50 minutes if the head wind were half as much. Find the head wind and the plane's air speed. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Against a head wind, Jeff computes his flight time for a trip of 2900 miles at 5 hours.
The flight would take 4 hours and 50 minutes if the head wind were half as much.
Find the head wind and the plane's air speed.
:
Let x = plane's air speed
Let y = headwind speed
and
.5y = half the headwind speed
:
Write two dist equations; dist = time * speed
:
Equation 1
5(x - y) = 2900
Simplify, divide both sides by 5
x - y = 580
and
equation 2
4(x - .5y) = 2900
which is (x - .5y) = 2900
Divide both sides by 29/6: results
x - .5y = 600
:
use elimination
x - .5y = 600
x - y = 580
--------------Subtraction eliminate x, find y
+.5y = 20
y = 40 mph is the head wind
then
x - 40 = 580
x = 580 + 40
x = 620 mph is the plane speed
:
:
Check solution in the 2nd original equation (620 - .5(40)) = (620 - 20) = (600) = 2900
29(100) = 2900
