SOLUTION: You drove 56 miles one way on a service call. On the return trip your average speed was 8 miles per hour faster and took 10 fewer minutes. What was the average speed on the return

Algebra ->  Average -> SOLUTION: You drove 56 miles one way on a service call. On the return trip your average speed was 8 miles per hour faster and took 10 fewer minutes. What was the average speed on the return       Log On


   



Question 238860: You drove 56 miles one way on a service call. On the return trip your average speed was 8 miles per hour faster and took 10 fewer minutes. What was the average speed on the return trip?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I write 2 equations, 1 for each trip
d%5B1%5D+=+r%5B1%5D%2At%5B1%5D
d%5B2%5D+=+r%5B2%5D%2At%5B2%5D
given:
d%5B1%5D+=+56 mi
d%5B2%5D+=+56 mi
r%5B2%5D+=+r%5B1%5D+%2B+8 mi/hr
t%5B2%5D+=+t%5B1%5D+-+1%2F6 (10 min is 1/6 hr)
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given:
d%5B1%5D+=+r%5B1%5D%2At%5B1%5D
(1) 56+=+r%5B1%5D%2At%5B1%5D
and
d%5B2%5D+=+r%5B2%5D%2At%5B2%5D
56+=+%28r%5B1%5D+%2B+8%29%2A%28t%5B1%5D+-+1%2F6%29
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(2) 56+=+r%5B1%5D%2At%5B1%5D+%2B+8t%5B1%5D+-+%281%2F6%29%2Ar%5B1%5D+-+4%2F3
Substitute (1) in (2)
56+=+56+%2B+8t%5B1%5D+-+%281%2F6%29%2Ar%5B1%5D+-+4%2F3
Subtract 56 from both sides
8t%5B1%5D+-+%281%2F6%29%2Ar%5B1%5D+=+4%2F3
Multiply both sides by 6
48t%5B1%5D+-+r%5B1%5D+=+8
and, from (1)
48%2A56%2Fr%5B1%5D+-+r%5B1%5D+=+8
2688%2Fr%5B1%5D+-+r%5B1%5D+=+8
Multiply both sides by r%5B1%5D
2688+-+%28r%5B1%5D%29%5E2+=+8r%5B1%5D
%28r%5B1%5D%29%5E2+%2B+8r%5B1%5D+-+2688+=+0
Use quadratic equation
r%5B1%5D+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+1
b+=+8
c+=+-2688
r%5B1%5D+=+%28-8+%2B-+sqrt%28+8%5E2-4%2A1%2A%28-2688%29+%29%29%2F%282%2A1%29+
r%5B1%5D+=+%28-8+%2B-+sqrt%28+64+%2B+10752+%29%29%2F2+
r%5B1%5D+=+%28-8+%2B-+sqrt%28+10816+%29%29%2F2+
r%5B1%5D+=+%28-8+%2B+104%29%2F2
r%5B1%5D+=+96%2F2
r%5B1%5D+=+48 (the negative answer is impossible)
r%5B2%5D+=+r%5B1%5D+%2B+8
r%5B2%5D+=+48+%2B+8
r%5B2%5D=+56
The speed on the return trip is 56 mi/hr
check answer:
(1) 56+=+r%5B1%5D%2At%5B1%5D
56+=+%28r%5B1%5D+%2B+8%29%2A%28t%5B1%5D+-+1%2F6%29
-----------------------
56+=+48%2At%5B1%5D
t%5B1%5D+=+1.167 hr (1 hr 10 min)
and
56+=+%2848+%2B+8%29%2A%28t%5B1%5D+-+1%2F6%29
56+=+56%2A%28t%5B1%5D+-+1%2F6%29
1+=+t%5B1%5D+-+1%2F6
6+=+6t%5B1%5D+-+1
6t%5B1%5D+=+7
t%5B1%5D+=+1.167 hr
OK