Question 238851: A vending machine accepts nickles, dimes and quarters. When the coins are emptied, the total value of the coins is found to be $24.15. Find the number of coins of each kind in the box, if there are twice as many nickles as quarters and 5 more dimes than nickels.
when solved can u show me the formula and the exact steps you took to solve it.. THANKS.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A vending machine accepts nickles, dimes and quarters.
When the coins are emptied, the total value of the coins is found to be $24.15.
Find the number of coins of each kind in the box, if there are twice as many nickles as quarters and 5 more dimes than nickels
:
.05n + .10d + .25q = 24.15
:
n = 2q
or
q = .5n
and
d = (n+5)
:
Now substitute (n+5) for d, and .5n for q in the Total$ equation, solve for n.
.05n + .10(n+5) + .25(.5n) = 24.15
:
Then use the above equations to find d and q.
:
Check your total in the original equation
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