SOLUTION: 1. 5.logbx+9.logby-3.logbz 2. log2x+log2(x-6)=4 3. logbx-(logby+logbz)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 1. 5.logbx+9.logby-3.logbz 2. log2x+log2(x-6)=4 3. logbx-(logby+logbz)       Log On


   



Question 238739:
1. 5.logbx+9.logby-3.logbz
2. log2x+log2(x-6)=4
3. logbx-(logby+logbz)

Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
Using log rules:
1. logb (ABC) = logb A + logb B + logb C
2. logb (A/B) = logb A - logb B
3. logb (A^n) = nlogb A
4. logb b = 1
5. logb = logb A1/n = (1/n)logb A n A
6. logb 1 = 0
7. logb (1/A) = logb 1 - logb A = -logb A
5*logbx+9*logby-3*logbz
Use rule 3 first
logb(x^5)+logb(y^9)-logb(z^3)
Use rule 1
logb((x^5 * y^9)/z^3))
log2x+log2(x-6)=4 (assuming base = 2)
log2(x^2-6x) = 4
x^2-6x = 2^4
(x-3)^2-9 = 16
x = 25^1/2 + 3
x = 8
logbx-(logby+logbz)
logbx-(logb y*z)
logb x/(y*z)