Question 238600: Use slopes to show that the square with virtices at (-2,5), (4, 5), (4, -1), and (-2, -1) has diagonals that are perpendicular.
I have looked over my chapter this week and I really need a refresher course quickly because it has been over 30 years since I have taken a math clas of this nature. This is only my first week and I have become really frustrated and lord knows, I have got to pass this class to get my degree in MR. I just need to learn how to function with all these x's and y's.
Thank you for your help, I really appreciated it.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Use slopes to show that the square with virtices at (-2,5), (4, 5), (4, -1), and (-2, -1) has diagonals that are perpendicular.
----------------------
Plot the points on a coordinate system so you can see where the
end points of the diagonals are.
----
1st pair is (-2,5),(4,-1)
slope of that segment is (-1-5)/(4--2) = -6/6 = -1
------------------------------------
2nd pair at (4,5),(-2,-1)
slope of that segment is (-1-5)(-2-4) = -6/-6 = 1
--------------------------------------
Since the product of the slopes is -1, the diagonals are perpendicular
to one another.
=======================================
Cheers,
Stan H.
|
|
|
