SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers in 19 less than the square of the largest number?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers in 19 less than the square of the largest number?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 238551: Find 3 consecutive numbers where the product of the smaller two numbers in 19 less than the square of the largest number?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Find 3 consecutive numbers
x, (x+1), (x+2)
:
where the product of the smaller two numbers in 19 less than the square of the largest number?
x(x+1) = (x+2)^2 - 19
:
x^2 + x = x^2 + 4x + 4 - 19
:
0 = x^2 - x^2 + 4x - x + 4 - 19
:
0 = 3x - 15
then
3x = 15
x = 15%2F3
x = 5 is the 1st number 6 = 2nd number and 7 the 3rd number
:
Check:
5*6 = 7^2 - 19