SOLUTION: 93xy is divisible by 72. then,
x=
y=
when this number is divided by 6,8,and 4, a there's always a reminder of 1?what is the least value of this number?
Algebra ->
Divisibility and Prime Numbers
-> SOLUTION: 93xy is divisible by 72. then,
x=
y=
when this number is divided by 6,8,and 4, a there's always a reminder of 1?what is the least value of this number?
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Question 238469: 93xy is divisible by 72. then,
x=
y=
when this number is divided by 6,8,and 4, a there's always a reminder of 1?what is the least value of this number? Answer by jsmallt9(3758) (Show Source):
You can put this solution on YOUR website! There is an error in the problem. Since 72 is divisible by 6, 8 and 4 and since 93xy is divisible by 72, 93xy must be divisible by 6, 8 and 4. There will be no (or zero) remainders.
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