SOLUTION: Find an equation in standard form for the line through (4, 1) and perpendicular to 3x + y = 5. A) x − 3y = 1 B) x + 3y = 7 C) 3x + y =13 D) 3x − y =11 E) non

Algebra ->  Linear-equations -> SOLUTION: Find an equation in standard form for the line through (4, 1) and perpendicular to 3x + y = 5. A) x − 3y = 1 B) x + 3y = 7 C) 3x + y =13 D) 3x − y =11 E) non      Log On


   

Question 238466: Find an equation in standard form for the line through (4, 1) and perpendicular to 3x + y = 5.
A) x − 3y = 1 B) x + 3y = 7 C) 3x + y =13 D) 3x − y =11
E) none of these
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that follow this relationship.
m1%2Am2=-1
3x%2By=5
y=-3x%2B5
m1=-3
-3%2Am2=1
m2=1%2F3
y=%281%2F3%29x%2Bb
Solve for b using (4,1)
1=%281%2F3%294%2Bb
1=%284%2F3%29%2Bb
b=-%281%2F3%29
y=%281%2F3%29x-%281%2F3%29
3y=x-1
-x%2B3y=-1
x-3y=1
Looks like A) is the correct answer.
+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+-3x%2B5%2C+%281%2F3%29x-%281%2F3%29%29+