SOLUTION: daniel has 19 coins in dimes and nickles. after spending 85 cents. he has 4 dimes and 2 nickles left. how many nickles did daniel have to start with ?
a) 2 b) 19 c) 7 d) 2
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a) 2 b) 19 c) 7 d) 2
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Question 238454: daniel has 19 coins in dimes and nickles. after spending 85 cents. he has 4 dimes and 2 nickles left. how many nickles did daniel have to start with ?
a) 2 b) 19 c) 7 d) 2 e) 46 Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! d = no. of dimes
n = no. of nickels
:
Just write an equation for each statement
:
daniel has 19 coins in dimes and nickles.
d + n = 19
or
n = (19-d); use this for substitution
:
after spending 85 cents. he has 4 dimes and 2 nickles left..
.10d + .05n - .85 = .10(4) + .05(2)
.10d + .05n - .85 = .40 + .10
.10d + .05n = .50 + .85
.10d + .05n = 1.35
Replace n with (19-d)
.10d + .05(19-d) = 1.35
.10d + .95 - .05d = 1.35
.10d - .05d = 1.35 - .95
.05d = .40
d =
d = 8 dimes
then
n = 19 - 8
n = 11 nickels
:
I don't agree with any of these answers. He started out with 11 nickels
Check this out
.10(8) + .05(11) =
.80 + .55 = 1.35
Subtract .85 and you .50 which is 4 dimes and 2 nickels
