SOLUTION: The length of a rectangle is 4 centimeters more than the width. the measure of the diagonal is 10 centimeters. Find the dimensions of the the rectangle I would appreciate help =

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Question 238288: The length of a rectangle is 4 centimeters more than the width. the measure of the diagonal is 10 centimeters. Find the dimensions of the the rectangle
I would appreciate help =]
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+4
L^2+W^2=10^2
(W+4)^2+W^2=100
W^2+8W+16+W^2=100
2W^2+8W+16-100=0
2W^2+8W-84=0
2(W^2+4W-42)=0
W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
W=(-4+-SQRT[4^2-4*1*-42])/2*1
W=(-4+-SQRT[16+168])/2
W=(-4+-SQRT184)/2
W=(-4+-13.565)/2
W=(-4+13.565)/2
W=9.565/2
W=4.78 ANS. FOR THE WIDTH
L=4.78+4=8.78 ANS. FOR THE LENGTH.
PROOF:
4.78^2+8.78^2=100
22.85+77.09=100
100~100