SOLUTION: A store sells turkey sandwiches for $5.00 and ham sandwiches for $4.00. The store sells 5 more turkey sandwiches than double the amount of ham sandwiches and the total sales are $1

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Question 238265: A store sells turkey sandwiches for $5.00 and ham sandwiches for $4.00. The store sells 5 more turkey sandwiches than double the amount of ham sandwiches and the total sales are $1089.00. How many of each are sold?
Found 2 solutions by alicealc, stanbon:
Answer by alicealc(293) About Me  (Show Source):
You can put this solution on YOUR website!
number of ham sandwiches sold = x
number of turkey sandwiches sold = 5 + 2x

4 * x + 5 * (5 + 2x) = 1089
4x + 5 * 5 + 5 * 2x = 1089
4x + 25 + 10x = 1089
14x + 25 = 1089
14x = 1089 - 25
14x = 1064
x = 1064/14
x = 76

number of ham sandwiches sold = x = 76
number of turkey sandwiches sold = 5 + 2x = 5 + 2*76 = 5 + 152 = 157

so, the store sells 157 turkey sandwiches and 76 ham sandwiches

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A store sells turkey sandwiches for $5.00 and ham sandwiches for $4.00.
The store sells 5 more turkey sandwiches than double the amount of ham sandwiches and the total sales are $1089.00.
How many of each are sold?
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Quantity Equation: t = 2h + 5
Value Equation:::: 5t + 4h = 1089
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Substitute for t in the value equation and solve for "h:
5(2h+5) + 4h = 1089
14h = 1064
h = 76 (# of ham sandwiches sold)
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Substitute into the Quantity Eq to solve for "y":
t = 2*76 + 5 = 157 (# of turkey sandwiches sold)
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Cheers,
Stan H.