SOLUTION: a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.

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Question 238264: a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.
Found 2 solutions by alicealc, stanbon:
Answer by alicealc(293) About Me  (Show Source):
You can put this solution on YOUR website!
first side (smallest) = x
second side = 10 + x
third side = 2x

perimeter = 54
x + 10 + x + 2x =54
4x + 10 = 54
4x = 54 - 10
4x = 44
x = 44/4
x = 11

so, the three sides of the triangle will be: 11 inches, 21 inches,and 22 inches

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.
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Let the smallest be "x".
The 2nd side is "x+10"
The 3rd side is "2x"
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Equation:
x + x+10 + 2x = 54
4x + 10 = 54
4x = 44
x = 11
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smallest = 11 inches
2nd = 11+10 = 21 inches
3rd = 2x = 22 inches
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Cheers,
Stan H.