SOLUTION: A rancher wants to use 400 feet of fencing to enclose a rectangular area or 7500 feet squared. What dementions should the rectangle have?
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Question 238221: A rancher wants to use 400 feet of fencing to enclose a rectangular area or 7500 feet squared. What dementions should the rectangle have? Answer by JimboP1977(311) (Show Source):
You can put this solution on YOUR website! x is the length of one side of the rectangle
y is the width of one side of the rectangle
x*y = 7500
2x+2y = 400
x+y = 200
y = 200 - x (1)
Therefore
x*y = x(200-x) = 7500
200x-x^2 = 7500
Divide both sides by -1
x^2-200x = -7500
Complete the square
(x-100)^2 - 10000 = -7500
x = 2500^0.5 + 100
x = 150
y= 7500/150
so dimensions are 150 feet by 50 feet
