SOLUTION: how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution

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Question 238210: how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
first mixture + second mixture = total mixture
0.20x + 0.10x = (2x + 50)(0.12)
Can you solve for x now?