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Question 238117: How do I find the missing coordinate? (3, ) is a solution of y= 4-3x..Trying to help son with homework and I never took algebra in high school. I guess I am learning right along with him. Thanks for any assistance.
Found 2 solutions by solver91311, Theo: Answer by solver91311(24713) (Show Source): Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! the equation is y = 4 - 3x.
the coordinates are (x,y) where x is the x-coordinate and y is the y-coordinate.
since you have (x,y) = (3,...), then the x-coordinate is 3.
substitute x = 3 in your equation and solve for y.
your equation becomes y = 4 - 3*3 = 4 - 9 = -5
your missing coordinate is -5 to make (x,y) = (3,-5)
a graph of your equation looks like:
the correct form of your equation is y = -3x + 4
The higher order term is always to the left of the lower order term.
order has to do with the exponents.
x^2 is higher order than x is higher order than 4
your equation is in the slope-intercept form of the equation for a straight line.
that form is y = mx + b where m is the slope and b is the y-intercept.
the slope of your equation is -3 and the y-intercept is 4
the y-intercept is the value of y when x = 0 which comes out to be 4 as can be seen in the graph.
the slope of -3 means that if x increases 1 unit, then y decreases 3 units.
that's why in your graph, when x = 0, y = 4, and when x = 1, y = 1, and when x = 2, y = -2
if you have the time, go through this beginning, intermediate, and college algebra online tutorial from west texas a&m. It will help you.
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