You can put this solution on YOUR website! to solve the following
8y^2=14y-5
8y^2 - 14y + 5 = 0
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Think of two numbers whose product is 5*8=40
and whose sum is -14.
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They are -10 and -4
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Rewrite the problem:
8y^2 - 10y - 4y + 5 = 0
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Factor the 1st two and the last two terms seperately:
2y(4y-5) - (4y-5) = 0
Factor again:
(4y-5)(2y-1) = 0
y = 5/4 or y = 1/2
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Cheers,
Stan H.