SOLUTION: g(x) = x2 + 3x h(x) = (x + 3)/2 Find: (h o g)(-1)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: g(x) = x2 + 3x h(x) = (x + 3)/2 Find: (h o g)(-1)      Log On


   

Question 237654: g(x) = x2 + 3x
h(x) = (x + 3)/2
Find: (h o g)(-1)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
g(x) = x2 + 3x
h(x) = (x + 3)/2
Find: (h o g)(-1)
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h[g(-1)] = h[(-1)^2+3*-1]
= h[1-3]
= h[-2]
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= (-2+3)^2
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= 1^2
= 1
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Cheers,
Stan H.