SOLUTION: How would i find an expression for the area of a triangle? The triangle is a 45-45-90 degree triangle with the two sides equaling x^2 and 2x^3. I got the equation y=1/2(2x^3)

Algebra ->  Exponents -> SOLUTION: How would i find an expression for the area of a triangle? The triangle is a 45-45-90 degree triangle with the two sides equaling x^2 and 2x^3. I got the equation y=1/2(2x^3)      Log On


   



Question 237417: How would i find an expression for the area of a triangle?
The triangle is a 45-45-90 degree triangle with the two sides equaling x^2 and 2x^3.
I got the equation y=1/2(2x^3)(x^2) and i am not sure if i am supposed to simplify it, or solve it, or if that is even the right equation.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The triangle is a 45-45-90 degree triangle with the two sides equaling x^2 and 2x^3.
I got the equation y=1/2(2x^3)(x^2) and i am not sure if i am supposed to simplify it, or solve it, or if that is even the right equation.
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Your equation looks good to me.
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You might also consider the following:
If the triangle is 45-45-90 the two sides must be equal.
Solve x^2 = 2x^3
Divide both sides by x^2 to get:
1 = 2x
x = 1/2
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Side x^2 = (1/2)^2 = 1/4
Side 2x^3 = 2(1/2)^3 = 2(1/8) = 1/4
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The area would be (1/2)(1/4)(1/4) = 1/32 sq. units
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Cheers,
Stan H.