SOLUTION: I'm working with Formulas and World Problems in Algebra
The problem is
The original temperature of gas was 33 degrees K. Its present pressure is 6.8mm and its present temperatur
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The problem is
The original temperature of gas was 33 degrees K. Its present pressure is 6.8mm and its present temperatur
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Question 237385: I'm working with Formulas and World Problems in Algebra
The problem is
The original temperature of gas was 33 degrees K. Its present pressure is 6.8mm and its present temperature is 27degrees K. What was the original pressure of the gas?
They gave us: P1/T1 = P2/T2
So that would work out to P1 x T1/T1 = P2 x T1/T2
which becomes P1 = P2 x T1/T2
which becomes 6.8mm x 33 degreesK/27 degreesK
It's a basic algebra problem that I've forgotten the process for can you please help? Answer by College Student(505) (Show Source):
You can put this solution on YOUR website! You got it right.
Since you're looking for P1 in this problem, you need to multiply T1 on both sides. Which gives you:
Now substitute values:
The unit of measure K (Kelvin Degrees) cancels, so you're left with mm.
