Question 237274: what is the shape of the graph of 9x+7y=-1000? how do you know?
please please please answer my question for once!!!!!!!!!!!!!!!!!!!!!! Answer by Theo(13342) (Show Source):
that would be the standard form for the equation of a straight line.
the standard form for the equation of a straight line is ax + by = c where:
a is the coefficient of the x term
b is the coefficient of the y term
c is the constant
it's a linear equation because none of the terms have a coefficient greater than 1.
the general form of the slope intercept form of this equation is y = mx + b where:
m is the slope and b is the y-intercept.
to convert from standard form to slope-intercept form, solve for y to get:
9x + 7y = -1000 is the original equation.
subtract 9x from both sides to get:
7y = -9x - 1000
divide both sides of the equation by 7 to get:
y = (-9/7)*x - (1000/7)
the slope is (-9/7) which replaces m from the general form.
the y-intercept is - (1000/7) which replaces b from the general form.
to graph this equation, you have to convert it to the slope-intercept form which is the same as solving for y.
the gtraph of this equation looks like:
you can see from the graph that when x = 0, y = -1000/7 = -142.
you can also see from the graph that when y = 0, x = -111.
you can't see exactly, but you can see that they're in the vicinity.
