SOLUTION: the present age of zain is 22 year and his father is 40 years .howmany years ago his father was three times of zain`s age?
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Question 237232
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the present age of zain is 22 year and his father is 40 years .howmany years ago his father was three times of zain`s age?
Answer by
rapaljer(4671)
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Let x = number of years ago
22-x = age of Zain x years ago
40-x = age of Zain's father x years ago
Father's age WAS 3 times Zain's age
40-x=3(22-x)
40-x = 66-3x
Add +3x to each side:
40-x + 3x = 66-3x+3x
40+2x = 66
Subtract 40 from each side:
2x=26
Divide by 2:
x= 13
Check: Zain's age was 22-13=9
Father's age was 40-13= 27, which is 3 times Zain's age.
Dr. Robert J. Rapalje