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| Question 237159:  an investment advisor invested 12000 into two accounts. one investment earned 7 % annual simple interest and the other investment earned 6.5% annual simple interest. the amount of interest for 1 year was 820. How much was invested at 6.5 %
 Answer by checkley77(12844)
      (Show Source): 
You can put this solution on YOUR website! .07X+.065(12,000-X)=820 .07X+780-.065X=820
 .005X=820-780
 .005X=40
 X=40/.005
 X=8,000 AMOUNT INVESTED @ 7%.
 12,000-8,000=4,000 AMOUNT INVESTED @ 6.5%
 PROOF:
 .07*8,000+.065*4,000=820
 560+260=820
 820=820
 
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