Question 236948: A rectangle is twice as long as it is wide and has a diagonal of length 25 cm. Find its dimensions. Found 2 solutions by edjones, checkley77:Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! L=2w
L^2+w^2=d^2
(2w)^2+w^2=25^2
4w^2+w^2=625
5w^2=625
w^2=125
w=sqrt(25*5)
w=5sqrt(5)cm
L=10sqrt(5)cm
.
Ed
You can put this solution on YOUR website! x^2+(2x)^2=25^2
X^2+4X^2=625
5x^2=625
x^2=625/5
x^2=125
x=sqrt125
x=11.18 cm. is the width.
2*11.18=22.36 cm. is the length.
Proof:
11.18^2+22.36^2=625
124.996+499.97=625
625~625
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