SOLUTION: algebra inverse function question how do I solve 2x+1/x-1 for the inverse when I can't get y by itself when I replace all of the x's with y's to find the inverse? help!

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Question 236838: algebra inverse function question
how do I solve 2x+1/x-1 for the inverse when I can't get y by itself when I replace all of the x's with y's to find the inverse?
help!
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=(2x+1)/(x-1)
y=( 2x+1)/(x-1)
y(x-1)=2x+1 Now we solve for x.
xy-y=2x+1
xy-2x=y+1 Get the x's on one side.
x(y-2)=y+1
x=(y+1)/(y-2)
y=(x+1)/(x-2) Switch x and y
f%5E%28-1%29%28x%29=%28x%2B1%29%2F%28x-2%29 the inverse.
.
Ed