SOLUTION: A water rocket is launched upward with an initial velocity of 48 ft/sec. Its height h, in feet, after t seconds is given by h = 48t - 16t2. After how many seconds will the object h

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Question 236757: A water rocket is launched upward with an initial velocity of 48 ft/sec. Its height h, in feet, after t seconds is given by h = 48t - 16t2. After how many seconds will the object hit the ground?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
on the ground, h = 0

factoring ___ 0 = 16t (3 - t)

16t = 0 ___ t = 0 ___ this is the launch

3 - t = 0 ___ 3 = t ___ this is the landing